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memmove() Move a Block of Bytes
#include <string.h>
#include <mem.h>
void *memmove(destin,source,n);
void *destin; Destination
void *source; Source
unsigned n; Number of bytes
memmove() copies a block of 'n' bytes from 'source' to 'destin'. If
the source and destination blocks overlap, the copy direction is
chosen so that overlapping bytes are copied correctly.
Returns: 'destin' is returned.
See Also:
memcpy()
memset()
memcmp()
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