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memmove()                Move a Block of Bytes

 #include   <string.h>
 #include   <mem.h>

 void       *memmove(destin,source,n);
 void       *destin;                     Destination
 void       *source;                     Source
 unsigned   n;                           Number of bytes

    memmove() copies a block of 'n' bytes from 'source' to 'destin'. If
    the source and destination blocks overlap, the copy direction is
    chosen so that overlapping bytes are copied correctly.

    Returns:    'destin' is returned.

See Also: memcpy() memset() memcmp()
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