@tobias hofer
>Was heist der kann nicht anders wegen dem internen aufbau?
Lies mal das Datenblatt zum Thema Monostable Operation.
>by a transistor inside the timer. Upon application of a negative
>trigger pulse of less than 1/3 VCC to pin 2, the flip-flop is
>set which both releases the short circuit across the capacitor
>and drives the output high.
Also der Zyklus wird mit einem negativen Puls gestartet. Sieht man auch
in dem Oszibild.
>for a period of t e 1.1 RA C, at the end of which time
>the voltage equals 2/3 VCC. The comparator then resets
>the flip-flop which in turn discharges the capacitor and
>drives the output to its low state. Figure 2 shows the waveforms
>During the timing cycle when the output is high, the further
>application of a trigger pulse will not effect the circuit so
>long as the trigger input is returned high at least 10 us before
>the end of the timing interval. However the circuit can
Bis 10us vor Ablauf der Kondensatorladung kann der Eingang TRIGGER
machen was er will, aber . . .
>NOTE: In monostable operation, the trigger should be driven
>high before the end of timing cycle.
Dort knallts bei dir. Deine Pulse mit <50% Duty cycle fallen hier durch.
MfG
Falk