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Linux: whitespace im Dateinamen: Wie kann ich das lösen?
Gast
#1427029
hello peoples, Assume a file containing a list of filenames. $cat list ein langer sommerabend.txt some other file Now, I want to copy them all at once and write therefor a loop like this $for i in $(cat list); do cp $i newdir; done Obviuosly I am running into the "whitespace in a filename" problem which I don't know how to solve. Does have somebody an advice or a working solution for me? Best regards, Daniel Enclose the $i in double quotes and you don´t have the problem anymore. Chris S. schrieb:
> Enclose the $i in double quotes and you don´t have the problem anymore.
Won't help because the input is already split into separate words by the
"for i in $(cat list)".
(while read i; do cp "$i" newdir; done) <list
Then use the command apply, or use sed instead. Apply is more simple and useful, check the man page. sed would be something like this, remove the echo after testing. sed -e 's/^[ \t]*/echo cp "/' -e 's,[ \t]*$," newdir,' list |sh Chris S. schrieb: > Then use the command apply, or use sed instead. > Apply is more simple and useful, check the man page. > > sed would be something like this, remove the echo after testing. > > sed -e 's/^[ \t]*/echo cp "/' -e 's,[ \t]*$," newdir,' list |sh Should this have any advantage over my solution?
Gast
#1427084
You have to set the InternalFieldSeperator-Variable to the newline char. Then bash will cut the input in lines, instead of token. http://wi-fizzle.com/article/276 xargs -d\\n cp -t newdir < list [offtopic] Usefull for filetransfers Windows <=> Linux... detox http://detox.sourceforge.net/ [/offtopic]
Gast
#1427281
cat list | while read FILE; do cp "$FILE" newdir; done
Gast
#1432662
Thank you. (while read i; do cp "$i" newdir; done) <list this one I like the most Antwort schreibenBitte melde dich an, um einen Beitrag zu schreiben. |
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